手游推荐
作者： 游氏手游网 发布时间: 2025-07-25 14:30
呵呵，这是我去年初学C语言时写的，当时水平低，高手就不要指责了~~~
#include<time.h>
#include<stdio.h>
#include<conio.h>
#include <stdlib.h>
char x,response;
int y,draw,win,loss;
void main()
{
c: draw = 0,win = 0,loss = 0;
d: system(cls);
printf(欢迎挑战\n\n);
printf(0:石头 1:剪子 2:布\n);
printf(\n请你出拳:);
if((x = getch()) == '0')
printf(石头);
else if(x == '1')
printf(剪子);
else if(x == '2')
printf(布);
else
{
printf(请按0-2\n按任意键继续\n);
getch();
goto d;
}
srand((unsigned)time(NULL));
y = rand()%3;
switch(y)
{
case 0:
printf(\n\n电脑出拳:石头\n\n);
break;
case 1:
printf(\n\n电脑出拳:剪子\n\n);
break;
case 2:
printf(\n\n电脑出拳:布\n\n);
break;
}
if(x == '0')
{
switch(y)
{
case 0:
printf(平局);
draw++;
break;
case 1:
printf(你赢了);
win++;
break;
case 2:
printf(你输了);
loss++;
break;
}
}
else if(x == '1')
{
switch(y)
{
case 0:
printf(你输了);
loss++;
break;
case 1:
printf(平局);
draw++;
break;
case 2:
printf(你赢了);
win++;
break;
}
}
else if(x == '2')
{
switch(y)
{
case 0:
printf(你赢了);
win++;
break;
case 1:
printf(你输了);
loss++;
break;
case 2:
printf(平局);
draw++;
break;
}
}
printf(\n\n你的战况:赢%d局 输%d局 平%d局, win, loss, draw);
if(win <= loss+draw)
{
printf(\n\n还不服气?\nY or N?\n);
response=getch();
if(response == 'Y' || response == 'y' || response == 13)
{
printf(\n战况清零?\nY or N?\n);
response = getch();
if(response == 'Y' || response == 'y' || response == 13)
{
goto c;
}
goto d;
}
}
else
{
printf(\n\n厉害,继续?\nY or N?\n);
response = getch();
if(response == 'Y' || response == 'y' || response == 13)
{
printf(\n战况清零?\nY or N?\n);
response = getch();
if(response == 'Y' || response == 'y' || response == 13)
{
goto c;
}
goto d;
}
}
}
你输入错误除了提示账号密码错误，其他没有是吧，还有你数据库信息填的对应不，密码加密方式对么，检查一下，还没搞好再找俺解决
/*
* 主类用与建立3个取款行为线程
*/
public class getMoney
{
public static void main(String args[])
{
card c=new card(100);
new Thread(c,ID-1).start();
new Thread(c,ID-2).start();
new Thread(c,ID-3).start();
System.out.println(3 ID using\t\t\t\t\t\t title 100$);
}
}
/*
* 实现RUNNABLE的银行卡类
*/
class card implements Runnable
{
private static int balance;
public card(int x)
{
this.balance=x;
}
public int view()
{
return balance;
}
public void get(int x)
{
this.balance=this.balance-x;
}
/*
* 同步方法块
*/
public synchronized void run()
{
int num=0;
while(this.view()>0)
{
System.out.println(操作时间:+num);
this.get(10);
System.out.println(Thread.currentThread().getName()+get 10$\t\t\t\t\t\t此时余额为+this.view());
num++;
}
if(this.view()<=0)
{
System.out.println(Thread.currentThread().getName()+取光了剩下所有的钱);
}
}
}
这个是银行取款的和受票类似，用了同步方法的方式
/*
* 主类用语建立3个售票窗口线程
*/
public class MyRun
{
public static void main(String args[])
{
My t=new My();
new Thread(t,t1).start();
new Thread(t,t2).start();
new Thread(t,t3).start();
System.out.println(开始售票..................);
}
}
/*
*实现RUNNABLE的售票窗口类
*/
class My implements Runnable
{
static int sum=20;
public void run()
{
synchronized(sldf)//同步语句块的方式
{
while(sum>0)
{
System.out.println(票号(+sum+)被卖掉了---------------------------------------售票窗口：+Thread.currentThread().getName());
sum--;
if(sum<=0)
{
System.out.println(售票窗口：+Thread.currentThread().getName()+的票卖完了！);
}
}
}
}
}
用了同步语句块的方式，你要4个窗口在主类多NEW一个线程就可以了
